Because the orbit is smooth, the ball has no mechanical energy loss when passing through point A, so it is known that the ball has no mechanical energy loss from the highest point to point C, so it is obtained from the law of conservation of mechanical energy: (MV 2)/2 = MGH (simplified as: V 2/2 = GH ... (2).
Combine (1)(2) to get H! ! !
2. It is achievable. It is also the law of conservation of energy. From point C to point O, the kinetic energy of the ball is converted into gravitational potential energy, and the ball has no mechanical energy loss from the highest point to point C. Similarly, from point C to point O, there is no other loss except that it is converted into gravitational potential energy, so it should be able to reach the original height of the ball (r+h), and the height of point O is r, so it must be reached.
3. After the ball leaves the O-point, do a flat throw. There are many ways to find the initial velocity. The simplest thing is that the speed (size) of the ball at this time should be equal to the speed of the ball passing through point A when it falls. Through the principle of flat throwing motion, it is not difficult to find out the position, speed direction and size of the ball falling back to AB orbit! There are too many words, so I won't elaborate here! ! ! !