∴ The bottom ABCD is rhombic, OA=OB=OC=OD, and the bottom ABCD is square.

Let the edge length be 1, and establish the spatial rectangular coordinate system as shown in the figure below:

Then s (0,0,22), o (0,0,0), b (0,22,0), a (22,0,0), e (24,0,24),

BE=（24，-22，24），OS=（0，0，22），

∵OS is the normal vector of plane ABCD, cos < be, OS > =1422× 32 = 66,

The sine value of the angle between Be and bottom ABCD is 66.

So the answer is 6. I have praised it and stepped on it. What is your evaluation of this answer? Comments put away Baiaolin (Shanghai) Trading Co., Ltd.

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