The idea of this question is as follows:

When 1 people are added to each car, the number of stevedores in this warehouse can be reduced by 1 if the total number of people in each car after the increase does not exceed the number of people needed by the warehouse. And if the total number of people in each car exceeds the number of people needed by the warehouse after the increase, then the number of people needed by the warehouse at this time is 1.

after this point is made clear, we can know that if one person is added to each car, four people will be added in general, and the number of people stationed in the warehouse will be reduced by *1. Therefore, when the number of vehicles does not exceed "the total number of people in each car does not exceed the number of warehouses needed by the warehouse", the number of people needed is the least, so there are four people in each car.

or if we assume that the number of people in each car is x and the total number of people is y, we can have the following functional relationship

when x <: The minimum value of =3 y=3-x+4-x+6-x+4-x+8-x+5-x+4x is 24

when x=4 y=23

when x=5 y=4*5+6-5+8-5=24

. =8 y=4x+8-x The minimum value is 29

when x >; The minimum value of =8 y=4x is 36

, so on the whole, the minimum value of 23 can only be obtained when x=4.