How much video memory is needed for a monitor with a resolution of 800×600 and 24-bit true color?
800×600×24÷8 = 1.44 MB
800×600 is the total number of pixels on the screen, 24-bit color is that a pixel to account for 24 bits, so 800×600×24 is the total number of bits, and then converted to 8-bit for a byte (Byte, abbreviated as B), to get 1440000B = 1440 KB = 1.44 MB