(1) Draw the light path as shown in the figure.

sinC=1n, Sinc = 11.6 < Sin 61, and C < 61 according to the critical angle formula.

When the light hits the AC surface for the first time, the incident angle is 61, which is greater than the critical angle C, and total reflection will occur.

According to the geometric relationship,. According to the geometric knowledge, if the reflected light is perpendicular to AC, some light will eventually emerge from AC, and the included angle between the emitted light and the AC plane is 91.

(2) The incident angle I of the light on the BC plane is 31, and the

refraction angle SINR = nsin31 = 1.6× 1.5 = 1.8 from n=sinrsini, and r = 53.