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Hello! If a deck of cards plays 18 arhats, and all the cards are 18, what is the odd number of this card? Ask for help. Thank you!
Hello, landlord! There is no such thing as a handsome man. I'd be happy to answer it for you.

According to the information provided by the landlord, this card is 88 (four happiness) plus 88 (four items), which is equal to 176 times.

If you are more detailed, it depends on how many hidden bars there are. There are 1 hidden bar 2 times (hidden bar), 2 hidden bars 6 times (double hidden bar), 3 hidden bars 16 times (3 hidden engravings) and 4 hidden bars 64 times (4 hidden engravings). There is no such thing as three dark bars and four dark bars, so it is counted as three dark engravings and four dark engravings.

It depends on what cards a pair will be. If it's 10 thousand pieces, strips and cakes, add 6 times the same color. If it is white, add 64 times.

If you can blossom on the bar again (8 times), the other three players will directly vomit blood and die.

I hope it helps you. Wish you success!