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Solving application problems with two series equations
Second quarter1:800+800x%; The third section is 800+800 x%+(800+800 x%) x%; The sum of the two quarters is 2 1 120000 yuan. So it's easy to do equations. Assumption: the growth rate is X%.

Solution: 800+800x%+800x%+(800+800x%) x% = 2112.

800+8x+800+8x+8x square% = 2121600+24x+8x square% = 212.

Multiply both sides by100:160000+2400x+8x squared =2 1 1200.

The square of 8X +2400X-5 1200=0 If both sides are divided by 8, the square of x +300X-6400=0.

The solution of cross multiplication: (x-20) (x+320) = 0x1= 20x2 =-320 is irrelevant.

A: The growth rate is 20%. Checking calculation: in the second quarter: 800+800× 20% = 800+160 = 960;

Section III: 960+960× 20% = 960+192 =1152; 960+1152 = 2112 (ten thousand yuan).

2. Assume that the width of the path is x meters. Solution: 40x+(26-x) x+(26-x) x = 40× 26-144× 6.

40X+26X-X square +26X-X square = 1040-864 92X-2X square = 176.

The square of 2X -92X+ 176=0 Divide two sides by 2: the square of x -46X+88=0.

The solution of cross multiplication: (X-44)(X-2)=0 X 1=44 irrelevant; X2=2

The width of this path is 2 meters. Checking calculation: 92X-2X square = 92x2-2x2 =184-8 =176 (square meter);

176+144× 6 =176+864 =1040 (square meter); 40×26= 1040 (square meter).