Then the heating of soybean milk through the R2 current I=
P heating |
U | tr>
1000W | tr>
220V |
(2) When this soymilk machine is in the holding state, it will work for 10 minutes, and the power consumed by the machine, W Holding=P Holding t=100W×10×60s=6×104J;
(3) The mass of the 1L of soymilk, m=ρSoymilkV= 1.0×103kg/m3×10-3m3=1kg,
Heating 1L of soymilk from 30℃ to 90℃ needs to absorb heat Q suction=cm(t-t0)=4.0×103?J/(kg?℃)×1kg×(90℃-30℃)=2.4×105J;
Electricity consumed by soymilk maker W heating=
Q Suck |
η |
2.4×105?J |
80% |
Needed to heat up time tHeat up=< table cellpadding="-1" cellspacing="-1" style="margin-right:1px">
3×105J |
1000W |
Answer: (1) the soybean milk machine is in the state of grinding and cooking, heating soybean milk through the current of R2 is 4.5A;
(2) the soybean milk machine in the state of heat preservation, work for 10 minutes, the soybean milk machine consumes 6 × 104J;
(3) 1L of soybean milk from 30 ℃ to 90 ℃ needs to absorb heat. (3) heating 1L of soybean milk from 30 ℃ to 90 ℃ need to absorb heat 2.4 × 105J; if the heating efficiency is 80%, it takes 300s.