Xiao Chen delivers 2 1 serving at a time, which is a multiple of 3.
Two people recite 135 books, which is a multiple of 9. Then the number of Chen Xiaoyun should be a multiple of 3.
Xiao Ming always brings even books, while Xiao Chen must bring odd books. Xiao Chen's times must be strange, too.
Then Xiao Chen may have delivered 3, 9, 15 ... times, and more times will exceed the total.
135 ÷ 2 1 = 6.43
Obviously, Xiao Chen has been lucky three times.
Xiao Ming is lucky (135-21× 3) ÷18 = 4 times.