2A+2B+ 10C= 100, which gives A=50-B-5C.
7A+4B+ 16C=200. If A=50-B-5C is brought into 7A+4B+ 16C=200, we get B=50- 19/3C.
17A+7B+30C=400 Bring B=50- 19/3C into 17A+7B+30C=400 to get C=6.
Substituting C=6 for B=50- 19/3C, we get B= 12.
Bring B= 12 and C=6 into A=50-B-5C, and get that A=8A needs 8 copies, b needs 12 copies and c needs 6 copies.