A ****4 pigeon cages with 27 pigeons.

The solution is as follows:

Solution 1 Let there be x pigeonholes.

6x+3+5=8x.

x=4.

6x+3=27 pigeons.

One **** 4 pigeon cages, 27 pigeons.

Solution 2: Let there be x pigeonholes and y pigeons, then

(1) 6*x+3=y.

(2) 8*x-5=y.

From (2)-(1), we get:

2*x-8=0

(3) x=4.

Substituting (3) into (1) gives

y = 27.

Answer:There were 27 pigeons and 4 pigeonholes.

Solution 3: Set x pigeonholes.

6x+3+5=8x

6x+8=8x

8x-6x=8

2x=4

x=4

6x+3=27

Answer:One **** 4 pigeonholes and 27 pigeons.

Expanded:

Equations must be equations, but equations are not necessarily equations.

Example: a+b=13 Fits an equation with unknowns. This is an equation and an equation.

1+1=2 , 100×100=10,000. these two formulas fit the equation, but there are no unknowns, so neither is an equation.

In the definition, an equation must be an equation, but there can be other equations, such as 1+1=2 and 100×100=10000, cited above, both of which are equations, and obviously equations have a larger range.

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